CUET UG 2025 — General Test Quantitative Reasoning

A number is divisible by 18 if it's divisible by both 2 and 9.

For 2469385422:

The last digit is 2, which is even, so the number is divisible by 2.

For divisibility by 9, the sum of all digits must be divisible by 9.

Sum of digits: $2 + 4 + 6 + 9 + 3 + 8 + 5 + 4 + 2 + 2$2+4+6+9+3+8+5+4+2+2

$$= 12 + 20 + 13$$=12+20+13

$$= 45$$=45

Since $45 \div 9 = 5$45÷9=5, the number is divisible by 9.

The number is divisible by both 2 and 9, so Statement (I) is true.

---

A number is divisible by 11 if the difference between the sum of digits at odd positions and the sum of digits at even positions (counting from right) is 0 or divisible by 11.

For 3475824638:

Digits from right to left: 8, 3, 6, 4, 2, 8, 5, 7, 4, 3

Odd positions (1st, 3rd, 5th, 7th, 9th from right): $8 + 6 + 2 + 5 + 4$8+6+2+5+4

$$= 25$$=25

Even positions (2nd, 4th, 6th, 8th, 10th from right): $3 + 4 + 8 + 7 + 3$3+4+8+7+3

$$= 25$$=25

Difference: $25 - 25$25−25

$$= 0$$=0

Since the difference is 0, Statement (II) is true.

---

Both Statement (I) and Statement (II) are true.