When a metal rod is stretched into a wire, the volume remains constant.
Original rod:
Length = 10 cm
Radius = 2 cm
Stretched wire:
Length = 40 m = 4000 cm
Radius = r (to find)
The rod is a cylinder with volume:
Volume = πr2h
Volume = π×(2)2×10
Volume = π×4×10
Volume = 40π cm³
The stretched wire is also a cylinder with volume:
Volume = π×r2×4000
Since the volume remains constant:
40π=π×r2×4000
40=r2×4000
r2=400040
r2=1001
r=101
r=0.1 cm
Therefore, the radius of the stretched wire is 0.1 cm.