1. Finding the value of y:
The angles at vertex A lie on a straight line. Therefore, the interior angle ∠A inside the triangle and the exterior angle 100∘ form a linear pair (adding up to 180∘):
\angle A = 180^\circ - 100^\circ = 80^\circ$ Now, looking inside the triangle $\triangle ABC$, the sum of all interior angles must be \$180^\circ$:\angle A + \angle B + y = 180^\circ$\$80^\circ + 50^\circ + y = 180^\circ
\130^\circ + y = 180^\circy = 50$
2. Finding the value of x:
The angles x∘ and y∘ lie on a straight horizontal line at vertex C, making them a linear pair:
x+y=180∘
x+50∘=180∘
$x=130
(Alternatively, by the exterior angle theorem, x is equal to the sum of the two opposite interior angles: x=∠A+∠B=80∘+50∘=130.)
Conclusion:
- x=130
- y=50
