CUET UG 2025 — General Test Arithmetic

Given:

• Compound Interest (CI) for 2 years = ₹369
• Rate of interest = 5% per annum
• Time period = 2 years

---

For compound interest, the amount after n years is:

$$A = P(1 + \frac{r}{100})^n$$A=P(1+100r​)n

Where A is the final amount, P is the principal, r is the rate, and n is the number of years.

---

Substituting the given values:

$$A = P(1 + \frac{5}{100})^2$$A=P(1+1005​)2

$$A = P(1.05)^2$$A=P(1.05)2

$$A = P \times 1.1025$$A=P×1.1025

---

Compound Interest is the difference between Amount and Principal:

$$CI = A - P$$CI=A−P

$$CI = P(1.1025) - P$$CI=P(1.1025)−P

$$CI = P(1.1025 - 1)$$CI=P(1.1025−1)

$$CI = P \times 0.1025$$CI=P×0.1025

---

Substituting CI = ₹369:

$$369 = P \times 0.1025$$369=P×0.1025

$$P = \frac{369}{0.1025}$$P=0.1025369​

$$P = 3600$$P=3600

---

Therefore, the principal amount is ₹3600.

The answer is option 2.