CUET UG 2025 — General Test Arithmetic

2025mcqmedium

If the difference between the compound and simple interests on a certain sum of money for 2 years at 20% per annum is ₹ 64, then the sum in ₹ will be:

Official previous-year question

Held on 26 May 2025 · Verified 13 Jul 2026.

Options

A
800
B
1200
C
640
D
1600

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Solution

Let the principal be $P$ .

Time = 2 years

Rate = 20% per annum

Simple Interest formula: SI = $\dfrac{P \times R \times T}{100}$

SI $= \dfrac{P \times 20 \times 2}{100}$

SI $= \dfrac{40P}{100}$

SI $= 0.4P$

Compound Interest formula: CI = $P \times [(1 + \dfrac{R}{100})^n - 1]$

CI $= P \times [(1 + \dfrac{20}{100})^2 - 1]$

CI $= P \times [(1.2)^2 - 1]$

CI $= P \times [1.44 - 1]$

CI $= 0.44P$

The difference between CI and SI is given as ₹64:

CI - SI $= 64$

$0.44P - 0.4P = 64$

$0.04P = 64$

$P = \dfrac{64}{0.04}$

$P = 64 \times 25$

$P = 1600$

Therefore, the sum is ₹1600.

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Solution

Let the principal be $P$ .

Time = 2 years

Rate = 20% per annum

Simple Interest formula: SI = $\dfrac{P \times R \times T}{100}$

SI $= \dfrac{P \times 20 \times 2}{100}$

SI $= \dfrac{40P}{100}$

SI $= 0.4P$

Compound Interest formula: CI = $P \times [(1 + \dfrac{R}{100})^n - 1]$

CI $= P \times [(1 + \dfrac{20}{100})^2 - 1]$

CI $= P \times [(1.2)^2 - 1]$

CI $= P \times [1.44 - 1]$

CI $= 0.44P$

The difference between CI and SI is given as ₹64:

CI - SI $= 64$

$0.44P - 0.4P = 64$

$0.04P = 64$

$P = \dfrac{64}{0.04}$

$P = 64 \times 25$

$P = 1600$

Therefore, the sum is ₹1600.

CUET UG 2025 — General Test Arithmetic

Options

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Solution

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CUET UG 2025 — General Test Arithmetic

Options

Did you get this right?

Solution

Your note

CUET UG Arithmetic in other years

More CUET UG Arithmetic questions

Other General Test topics for CUET UG

General Knowledge

Logical Reasoning

Quantitative Reasoning

Geometry

Current Affairs

Keep practicing Arithmetic