CUET UG 2025 — General Test Arithmetic

Total number of purses = 10

Average lipsticks per purse = 25

Total lipsticks = $10 \times 25 = 250$10×25=250

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To maximize the number of lipsticks in one purse, we minimize the number in the other 9 purses.

Given constraints:

• Each purse must have at least 8 lipsticks
• No two purses can have the same number of lipsticks

The minimum possible values for 9 purses are: 8, 9, 10, 11, 12, 13, 14, 15, 16

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Sum of lipsticks in these 9 purses:

$$8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16$$8+9+10+11+12+13+14+15+16

$$= (8 + 16) + (9 + 15) + (10 + 14) + (11 + 13) + 12$$=(8+16)+(9+15)+(10+14)+(11+13)+12

$$= 24 + 24 + 24 + 24 + 12$$=24+24+24+24+12

$$= 108$$=108

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Maximum lipsticks in the 10th purse:

$$= 250 - 108$$=250−108

$$= 142$$=142

Therefore, the maximum number of lipsticks in any purse is 142.